336=-16t^2+200t

Solution for 336=-16t^2+200t equation:

336=-16t^2+200t

We move all terms to the left:

336-(-16t^2+200t)=0

We get rid of parentheses

16t^2-200t+336=0

a = 16; b = -200; c = +336;
Δ = b2-4ac
Δ = -2002-4·16·336
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-136}{2*16}=\frac{64}{32}
=2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+136}{2*16}=\frac{336}{32}
=10+1/2
$